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0=6x^2-10x+10
We move all terms to the left:
0-(6x^2-10x+10)=0
We add all the numbers together, and all the variables
-(6x^2-10x+10)=0
We get rid of parentheses
-6x^2+10x-10=0
a = -6; b = 10; c = -10;
Δ = b2-4ac
Δ = 102-4·(-6)·(-10)
Δ = -140
Delta is less than zero, so there is no solution for the equation
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